🐍 [Day 3] check_password()

Morning! 😃 ☕️

Halfway through the week.

The length check is still gone from yesterday - and today the heart of the loop disappears too. About half the function is blank now.

Before you scroll, try saying the missing lines out loud. Even a whisper over your coffee counts - speaking a line is a different muscle from reading it, and it's the one that sticks.

In today's email...

• 🐍 Day 3: The loop's inside vanishes - half the function is blank

• 💭 How a for loop hunts through the password

• ☕ Paste your version and watch Ada run it

THE FUNCTION 🐍

def check_password(password):
    ____________________
        ____________________
    has_number = False
    for char in password:
        ____________________
            ____________________
    if has_number:
        return "Strong"
    return "Medium"

TODAY'S LINE 💭

The two new blanks live inside the loop:

        if char.isdigit():
            has_number = True

The line still showing above them - for char in password: - is the loop itself. It takes the password and hands you its characters one at a time, calling each one char. First the loop sees "p", then "a", then "s", and so on to the end.

Each time through, the blanked lines ask a question: if char.isdigit(): - "is this character a digit?" The moment the answer is yes, has_number = True records it. Once it's True, it stays True, even if the rest of the characters are letters.

That's the everyday shape of a loop: set up an answer before you start (has_number = False, still visible on line 4), then walk the data and update the answer as you learn more. You now have both halves - the setup and the search.

WITH ADA ☕

Fill the loop back in from memory, then take the whole thing to Ada at py-and-jam.com and let her run it.

This is the real test: if your loop is right, "letters" comes back one way and "letters1" another - that single 1 is what your loop is hunting for. Watch it land.

ANSWER KEY ✅

Today's blanked lines - the digit check inside the loop:

        if char.isdigit():
            has_number = True

The full function:

def check_password(password):
    if len(password) < 8:
        return "Weak"
    has_number = False
    for char in password:
        if char.isdigit():
            has_number = True
    if has_number:
        return "Strong"
    return "Medium"

See you tomorrow - only the verdict lines are left to fade. 🐍 The Py & Jam Team